First slide

Solubility product(KSP)

Question

If $K_{sp} for {HgSO}_{4}$ is $6.4 \times 10^{- 5},$ then solubility of this substance in mole per $m^{3}$ is

Easy

A

$8$
B

$6.4 \times 10^{- 5}$
C

$8 \times 10^{- 6}$
D

none of these

Solution

$K_{sp} = s^{2}$ $s = \sqrt{K_{sp}} = \sqrt{6.4 \times 10^{- 5}}$
$s = 8 \times 10^{- 3}$ $s = 8 mol / m^{3}$

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