Q.

If the KSP of a sparingly soluble salt, A3B2 in water is 1.08 × 10–8 mol5L–5, its solubility in mol L–1 is

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a

10-1

b

10-3

c

10-2

d

1.08 x 10-2

answer is C.

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Detailed Solution

A3B2(s)⇌A3B2(aqS)→3A+x(3Saq)+2B-y2S(aq) 3x=2yKsp = (3S)3 × (2S)2 = 108S51.08 × 10-8 = 108 × S5 S = 10-2

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If the KSP of a sparingly soluble salt, A3B2 in water is 1.08 × 10–8 mol5L–5, its solubility in mol L–1 is