If 1 L of NH3 is formed at STP according to reaction,N2+3H2⟶2NH3moles of H2 required under identical condition would be

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3 mol

1.5 mol

0.067 mol

0.134 mol

answer is C.

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Detailed Solution

N2 + 3H2⟶2NH3 1 mol 3 mol 2 mol 1 L 3 L 2 L 2LNH3 is from =3LH2∴1LNH3 is from =1.5LH2=1.5L22.4Lmol−1=0.067mol

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