If the mass of an electron is 9.11×10-31 kg, and uncertainty in position is 10-8 m, the uncertainty in velocity would be

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10-4ms-1

104ms-1

10-8ms-1

108ms-1

answer is B.

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Detailed Solution

∆v=h4πm∆x=6.626×10-34 kg m2s-14×3.142×9.11×10-31 kg×10-8 m=104 ms-1

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