If 0.5 mol of BaCl2, is mixed with 0.2 mol of Na3PO4, the maximum moles of Ba3(PO4)2 obtained is:

3BaCl2+2Na3PO4→Ba3PO42+6NaClLimiting reactant is which produce minimum moles of products.The limiting reactant is Na3PO4, the no. of moles of Ba3(PO4)2 produced = 0.2/2 = 0.1 mol.