If the molar conductivities at infinite dilution of NH4CI, NaOH and NaCl respectively are 120.8, 210.4 and 110 S cm2 mo1-1. Then the limiting molar conductivity of NH4OH is equal to

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389.9 S cm2 mo1-1

221.2 S cm2 mo1-1

228.4 S cm2 mo1-1

199.6 S cm2 mo1-1

answer is B.

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Detailed Solution

ΛmNH4OH∞=ΛmNH4Cl∞+ΛmNaOH∞−Λm(NaCl)∞= 120.8 + 210.4 – 110.0ΛmNH4OH∞=221.2ohm−1cm2mol−1

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