If 0.50 mole of BaCl2 is mixed with 0.20 mole of Na3PO4, the maximum number of moles of Ba3PO42 that can be formed is

(i) Write balanced chemical equation for chemical change.(ii) Find limiting reagent.(iii) Amount of product formed will be determined by amount of limiting reagent.The balanced equation is :3BaCl23moles0.5moles  +  2Na3PO42 moles0.2moles      →  Ba3PO42+6NaCl1mole       ?                       0.5moles of BaCl2 require 0.5×23(>0.2)moles of Na3PO4Hence Limiting  reagent  is Na3PO4  0.2 mol,  BaCl2  is in  excess.From the above equation :       2.0  moles  of Na3PO4  yields →1 mole of  Ba3PO42∴   0.2  moles of Na3PO4  will  yield →           ?                                            =12  ×  0.2  =0.1  mol.