If 0.5 mole of BaCl2 is mixed with 0.20 mole of Na3PO4,the maximum number of moles of Ba3(PO4)2, then can be formed is

3BaCl2+2Na3PO4⟶6NaCl+Ba3PO42[3mol 2mol               6mol 1mol] Given ⇒0.5mol of BaCl2 and 0.2mol of Na3PO4 To find the limiting reagent: 2mol of Na3PO4⇒3mol pf BaCl20.2mol of Na3PO4⇒0.3mol of BaCl2∴Na3PO4 is the limiting reagent ∴2mol of Na3PO4⇒1mol of Ba3PO420.2mol of Na3PO4⇒0.1mol of Ba3PO42