If 0.5 mole of BaCl2 is mixed with O.2O mole of Na3PO4 the maximum number of Ba3PO42 that can be formed is

3BaCl2+2Na3PO4⟶Ba3PO42+6NaCl0.5               0.2                0.1From the above equation, it is very clear,that,Na3PO4 is the limiting reagent∵2 moles of Na3PO4 gives Ba3PO42 = l mol∴0.2 mole of Na3PO42 giyes Ba3PO42 = 12×0.2= 0.1 mol