If 1 12 moles of oxygen combine with Al to form Al2O3 the weight of Al used in the reaction is (Al = 27)

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27 g

54 g

49.5 g

31 g

answer is B.

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Detailed Solution

2Al+ 32 O2 → Al2O3According to equation 32 mole of O2 combines with 2 moles Al.2 mole Al=54 g

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