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If one starts with 1 Curie (Ci) of radioactive substance (t½: 15 hr), the activity left after a period of two weeks will be about 0.02 x μCi. Find the value of x.

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answer is 9.

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Detailed Solution

k=0.69315hr=0.0462hr−1k=2.314×24hrlog⁡c0ct0.0462hr−1=2.314×24hrlog⁡1CictSolve for ct :∴ct = 1.82 × 10-7Ci ≈ 0.18 μCi = 0.02x μCi ∴ x = 9

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If one starts with 1 Curie (Ci) of radioactive substance (t½: 15 hr), the activity left after a period of two weeks will be about 0.02 x μCi. Find the value of x.