Q.

If  Rf=106[Ag+][NH3]2 lit2.mol−2.s−1 & Rb=2×10−2[Ag(NH3)2]+, then "instability constant" for Ag++2NH3⇌[Ag(NH3)2]+(aq) is  (Rf, Rb= Rates of forward & backward reactions)

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a

10−6

b

2×10−2

c

2×10−8

d

2×104

answer is C.

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Detailed Solution

Ag++2NH3⇌[Ag(NH3)2]+      Kc=? At equilibrium state rf=rb 106[Ag+][NH3]2=2×10−2[Ag(NH3)2]+ ⇒[Ag(NH3)2]+[Ag+][NH3]2=1062×10−2=1082 ∴ Instability constant=1Kc=1(1082)=2×10−8
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