If Rf=106[Ag+][NH3]2 lit2.mol−2.s−1 & Rb=2×10−2[Ag(NH3)2]+, then "instability constant" for Ag++2NH3⇌[Ag(NH3)2]+(aq) is (Rf, Rb= Rates of forward & backward reactions)
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a
10−6
b
2×10−2
c
2×10−8
d
2×104
answer is C.
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Detailed Solution
Ag++2NH3⇌[Ag(NH3)2]+ Kc=? At equilibrium state rf=rb 106[Ag+][NH3]2=2×10−2[Ag(NH3)2]+ ⇒[Ag(NH3)2]+[Ag+][NH3]2=1062×10−2=1082 ∴ Instability constant=1Kc=1(1082)=2×10−8