If the radius of first Bohr orbit is a, then de-Broglie wavelength of electron in 3rd orbit is nearly.
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
2πa1
b
6πa1
c
9πa1
d
16πa1
answer is B.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
According to Bohr theorymvr=nh2π∴ hmv=2πrnAccording to de−Broglieλ=hmv∴ λ=2πrnwhere r is the radius of the orbit having principal quantum number = n∵ a3a1=91 r ∝ n2 here a3 = radius of 3rd orbit∴ λ =2π × 9a13=6πa1