If the rate of reaction is 2.0 × 10-3 mol L-1 s-1 at 50°C and 1.6 × 10-2 mol L-1 s-1 at 80°C, then what will be the temperature coefficient of the reaction?

Since temperature coefficient is the ratio of rate constant or rate of reaction at 35° and 25°C. i.e., for 10°C or 10 K rise of temperature. Let temperature coefficient is represent by μ.r2r1=(μ)ΔT/101.6×10−22.0×10−3=(μ)30/10⇒8=μ3,⇒(2)3=(μ)3∴μ=3