If a second order reaction involving a single reactant , 25% complete in 20 minutes then what is its half life if initial concentration of the reactant is being made double at the same temperature.
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a
50 min
b
30 min
c
60 min
d
15 min
answer is B.
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Detailed Solution
1C−1C0=kt (for 2nd order reaction)134C0−1C0=k×20112(2C0)−12C0=k×t1/2⇒ 13C012C0=20t1/2⇒23=20t1/2⇒ t1/2=30 minutes