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Q.

If the solubility of lithium sodium hexafluoride aluminate, Li3Na3(AlF6)2 is ‘s’ mol/lit, its solubility product is equal to:

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a

729s8 (mole/lit)8

b

1112s8 (mole/lit)8

c

3900s8(mole/lit)8

d

2916s8(mole/lit)8

answer is D.

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Detailed Solution

Li3Na3AlF62→3Li+3s+3Na+3s+2AlF63−2sKsp=(3s)3(3s)32s2=2916s8(mole/lit)8
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