First slide

Solubility product(KSP)

Question

If the solubility product of CuS in 6 x 10^-16, calculate the maximum molarity of CuS in an aqueous solution.

Moderate

A

$2 .45 \times 10^{- 8} mol L^{- 1}$
B

$2 .45 \times 10^{- 7} mol L^{- 1}$
C

$2 .45 \times 10^{- 6} mol L^{- 1}$
D

$2 .45 \times 10^{- 5} mol L^{- 1}$

Solution

Maximum molarity of CuS in aqueous solution = Solubility of CuS in moL^-1
$CuS ⇌ {Cu}^{2 +} + S^{- 2}$
$\begin{array}{l} K_{sp} = [{Cu}^{2 +}] [S^{2 -}] = S \times S = S^{2} \\ S^{2} = 6 \times 10^{- 16} \\ S = \sqrt{6 \times 10^{- 16}} = 2 .45 \times 10^{- 8} {molL}^{- 1} \end{array}$

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