First slide

Solubility product(KSP)

Question

If the solubility product of MOH is $1 \times 10^{- 10}$ mol² dm^-6 then the pH of its aqueous solution will be

Moderate

Solution

$\large MOH\left( s \right) \rightleftharpoons \mathop {MOH}\limits_S \left( {aq} \right)\xrightarrow{{}}\mathop {{M^ + }}\limits_S \left( {aq} \right) + \mathop {O{H^ - }}\limits_S \left( {aq} \right)$

$\large {S^2} = {K_{SP}} = {10^{ - 10}}$
$\large {\Rightarrow S = {10^{ - 5}}$
$\large {P^{OH}} = - \log \left[ {O{H^ - }} \right] = 5$
$\large {P^H} = 9$

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