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If the speed of tight is 3.0×108 ms-1, calculate the distance covered by light in 2.00 ns.

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By Expert Faculty of Sri Chaitanya
a
0.10 m
b
0.81 m
c
0.11 m
d
0.6 m

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detailed solution

Correct option is D

2.00 ns=2.00×10-9 s 1 ns=10-9 sDistance covered = Speed x Time=3.0×108 ms-1×2.0×10-9 s=6.0×10-1 m=0.6 m


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