First slide

Nernst Equation

Question

If the standard electrode protential of Cu²⁺/ Cu electrode is 0.34 V, what is the electrode potential at 0.01 M concentration of Cu²⁺? (T = 298⁰K)

Moderate

A

0.399 V
B

0.281 V
C

0.222 V
D

0.176 V

Solution

Reduction of Cu⁺² is represented as Cu⁺² + 2e^- → Cu
Applying Nernst equation
${E_{C{u^{ + 2}}/Cu}} = E_{C{u^{ + 2}}/Cu}^0 - \frac{{0.0591}}{2}\log \frac{{\left[ {Cu} \right]}}{{\left[ {C{u^{ + 2}}} \right]}}$
$= 0.34 + 0.03\log {10^{ - 2}} = 0.34 - 0.06 = 0.28V$

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