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If the standard molar enthalpy of formation of CaOs,CO2g and CaCO3s is –635, –393 and –1207kJ mol–1 respectively, the ∆rH in kJ/mole for the reaction, CaCO3s→CaOs+CO2g is

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answer is 4.

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Detailed Solution

∆rH=∆fHCaO+∆fHCO2-∆fHCaCO3; ∆rH=-635+-393--1207 kJ; ∆rH=+179 kJ ;

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