If the standard molar enthalpy of formation of CaOs,CO2g and CaCO3s is –635, –393 and –1207kJ mol–1 respectively, the ∆rH in kJ/mole for the reaction, CaCO3s→CaOs+CO2g is

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

answer is 4.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

∆rH=∆fHCaO+∆fHCO2-∆fHCaCO3; ∆rH=-635+-393--1207 kJ; ∆rH=+179 kJ ;

Watch 3-min video & get full concept clarity