First slide

Faraday's Laws

Question

If three faradays of electricity are passed through the solutions of AgNO₃, CuSO₄ and AuCl₃, the molar ratio of the cations deposited at the cathode will be

Easy

A

1:1:1
B

1:2:3
C

3:2:1
D

6:3:2

Solution

Number of equivalents =number of moles x valency (n).
1 F deposits always 1 equivalent of any substance .
$Ratio\,ofmoles\,\,of\,each\,metal\,deposited = \frac{3}{1}:\frac{3}{2}:\frac{3}{3} = 3:\frac{3}{2}:1 = 6:3:2$

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