If three faradays of electricity are passed through the solutions of AgNO3, CuSO4 and AuCl3, the molar ratio of the cations deposited at the cathode will be
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a
1:1:1
b
1:2:3
c
3:2:1
d
6:3:2
answer is D.
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Detailed Solution
Number of equivalents =number of moles x valency (n).1 F deposits always 1 equivalent of any substance .