If two litres of air is passed repeatedly over heated copper and heated Mg till no further reduction in volume takes place, the volume finally obtained will be approximately.
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a
200 ml
b
20 ml
c
0 ml
d
10 ml
answer is B.
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Detailed Solution
Air contains 99% O2 and N22Mg+O2→2MgO3Mg+N2→Mg3N2Gases adsorbed=2000×99100=1980Gases left 2000 - 1980 = 20 ml.
If two litres of air is passed repeatedly over heated copper and heated Mg till no further reduction in volume takes place, the volume finally obtained will be approximately.