If two substances A and B have = 1 : 2and have mole fraction in solution 1 : 2, then mole fraction of A in vapours is
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answer is 4.
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Detailed Solution
According to Raoult's law, Ptot=PA+PB Where PA,PB = V.P of components A & B in a mixture XA, XB = M.F of components in liquid phase According to Dalton's law, PA = Ptot YA ; PB = PtotYBYA , YB = M.F of components in vapour phaseGiven, = 1:2 XA:XB = 1:2 YA =? ; YB =4 YAYA+YB = 15YA = 1YA = 0.2