Q.

If vapour pressures of pure liquids 'A' & 'B' are 300 and 800 torr respectively at 25oC. When these two liquids are mixed at this temperature to form a solution in which mole percentage of ‘B’ is 92, then the total vapour pressure is observed to be 0.95 atm. Which of the following is true for this solution.

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ΔVmix>0

ΔHmix<0

ΔVmix=0

ΔHmix=0

answer is B.

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Detailed Solution

According to Raoult's law PT=(0.08×300+0.92×800) torr =(24+736) torr = 760 torr = 1 atm Pexp.= 0.95 atm < 1 atm Hence solution shows negative deviationso ΔHmix<0, and ΔVmix<0.

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