If the velocity of electron increases, its specific charge
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a
increases
b
decreases
c
remains constant
d
may increase or decrease
answer is B.
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Detailed Solution
Mass of electron=rest mass of electron1−V2C2V = Velocity of electron C = Velocity of lightAs velocity of electron increases, V2C2 increases and 1−V2C2 decreases as denominator decreases mass of electron increases (rest mass electron is a constant) and thus e/m (specific charge) decreases