Q.

If the velocity of electron increases, its specific charge

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a

increases

b

decreases

c

remains constant

d

may increase or decrease

answer is B.

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Detailed Solution

Mass of electron=rest mass of electron1−V2C2V = Velocity of electron C = Velocity of lightAs velocity of electron increases, V2C2  increases and 1−V2C2  decreases as denominator decreases mass of electron increases (rest mass electron is a constant) and thus e/m  (specific charge) decreases
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