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Q.

If the weight of 5.6 lit of gas at NTP is 11 g, the gas may be (at.wt of P=31, N=14, O=16 and Cl=35.5 )

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a

PH3

b

COCl2

c

NO

d

N2O

answer is D.

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Detailed Solution

M=WRTPV       =11×22.4273×2731×5.6       =44 ∴  The gas is N2O
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