If x g is the mass of NaHC2O4 is required to neutralize 100 ml of 0.2 (M) NaOH and y g is required to reduce 100 ml of 0.02 (M) KMnO4 in acidic medium, then

Let mol wt. of NaHC2O4=M∴ xM=100×0.2×10−3=20×10−3             . . . .(1)25×yM=100×0.02×10−3=2×10−3Dividing equation (1) by equation (2), we get52×xy=10  or  x=4y