Ina solid, oxide ions are arranged in ccp, cations A occupy(1/8) of the tetrahedral voids and cations B occupy (1/4)th of the octahedral voids. The formula of the compound is
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a
ABO4
b
AB2O3
c
A2BO4
d
AB4O4
answer is A.
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Detailed Solution
No. of O2â=8Ã18+6Ã12=4 No. of A=18Ã8=1 No. of B=14Ã4=1