Q.

Increasing amount of HgI2 is added to 1 litre of an aqueous solution containing 0.1 mole of KI. Which of the following graphs does represent the variation of depression in freezing point of the resulting solution with the amount of HgI2 added?

see full answer

Want to Fund your own JEE / NEET / Foundation preparation ??

Take the SCORE scholarship exam from home and compete for scholarships worth ₹1 crore!*

An Intiative by Sri Chaitanya

answer is C.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

2KI(aq)+HgI2(s)→K2HgI4(aq) or 2K++2I−+HgI2(s)→2K++[HgI4]2−As a result of complex ion formation, the number of mole particles in the solution decreases in the ratio 4 : 3. So ΔTf decreases until all the I- ions are consumed with 0.05 moles of HgI2. The excess of HgI2 remain insoluble. Hence after 0.05 moles of HgI2, the freezing point of solution remains constant.

Watch 3-min video & get full concept clarity

Result Producing online coaching for JEE/NEET of south India

Largest All India Test Series for JEE/NEET

Best Books for IIT JEE

Best Books for NEET