Increasing order freezing points.I. 0.1 M ethanol II. 0.1 M Ba3(PO4) 2III. 0.1 M Na2SO4

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II < III < I

II < I < II

I < III < II

III < I < II

answer is A.

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Detailed Solution

Freezing point is higher if ∆Tf is lower (depends on meff).⇒ 0.1 M Ba3(PO4) 2 < 0.1 M Na2SO4 < 0.1 M ethanol II < III < I

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