Increasing order of $Δ_{o}$ of the following complex is

Moderate

A

$Cr {({NH}_{3})}_{6}^{3 +} < Cr {(H_{2} O)}_{6}^{3 +} < Cr {({NO}_{2})}_{6}^{3 -}$
B

$Cr {(H_{2} O)}_{6}^{3 +} > Cr {({NH}_{3})}_{6}^{3 +} > Cr {({NO}_{2})}_{6}^{3 -}$
C

$Cr {(H_{2} O)}_{6}^{3 +} < Cr {({NH}_{3})}_{6}^{3 +} < Cr {({NO}_{2})}_{6}^{3 -}$
D

$Cr {({NH}_{3})}_{6}^{3 +} < Cr {({NO}_{2})}_{6}^{3 -} < Cr {(H_{2} O)}_{6}^{3 +}$

Solution

For the same cation, stronger the ligand, higher the $Δ_{o}$
$Cr {(H_{2} O)}_{6}^{+ 3} < Cr {({NH}_{3})}_{6}^{+ 3} < Cr {({NO}_{2})}_{6}^{- 3}$

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