Initial and final state of gas are represented respectively by P1,V1,T1 and P2,V2,T2. The pressure and volume of the gas during process is related by PVn = constant. Therefore net reversible work done is
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a
P2V2−P1V1(1−n)
b
P2V2−P1V1(n−1)
c
−P2V2P1V1
d
−PΔV
answer is B.
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Detailed Solution
PVn=c, where c is a constant ∴ P=c/Vn∴ Work done, ΔW=−∫V1V2 PdV=−c∫V1V2 dVVn=c(n−1)1V2n−1−1V1n−1 or ΔW=1(n−1)P2V2−P1V1