Q.

Insulin (C2H10O5)n is dissolved in a suitable solvent and the osmotic pressure (π) of solution of various concentrations (g/cc) C is measured at 20oC. The slope of the plot of π against ‘C’ is found to be 4.65×10−3. The molecular weight of insulin is

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4.8×105

9×105

3×105

5.17×106

answer is D.

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Detailed Solution

πV=wBmB×RTπ=(wBV)RTmBπ=C×RTmB×1000...(i)where C = concentration in g/cc, When a graph of the osmatic pressure vs concentrationgr/ml is plotted, the slopem is Slope m=RTmB×1000mB=RTSlope×1000mB=0.0821×293×10004.65×10−3=5.17×106J/mol

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