The inversion of cane sugar proceeds with half-life of 500 min at pH = 5 for any concentration of sugar. However, if pH = 6, the half-life changes to 50 min.Expression for the rate law for sugar inversion is
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
r=k[ sugar ]1H+0
b
r=k[ sugar ]0H+1
c
r=k[ sugar ]2H+0
d
r=k[ sugar ]1H+1
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
At, pH = 5, the half-life is 500 min for all concentration of sugar, i.e. t1/2∝[ sugar ]. Thus, the reaction is of first order with respect to sugar.Now, rate =k[ sugar ]1H+mAlso for H+t1/2∝H+1−m ∴ 500∝10−51−m …….(i) 50∝10−61−m …….(ii)∴ 10=(10)(1−m) or (1−m)=1 m=1−1=0 rate =k[ sugar ]1H+0