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Q.

Ionisation energy of He+  is  19.6  ×10−18  J  atom−1. The energy of the first stationary state (n = 1) of Li2+  is

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a

4.41  ×10−16  J  atom−1

b

−4.41  ×10−17

c

−2.2  ×10−15  J  atom−1

d

8.82  ×10−17  J  atom−1

answer is B.

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Detailed Solution

IE=−E1E1  for  He+=−19.6  ×10−18  J  atom−1E1He+E1Li2+ = ZHe+2ZLi2+2−19.6  ×10−18E1Li2+=49Or      E1Li2+=−19.6  ×9 × 10−184=−4.41 × 10−17  J  atom−1
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