Ionisation energy of He+ is 19.6 ×10−18 J atom−1. The energy of the first stationary state (n = 1) of Li2+ is

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4.41 ×10−16 J atom−1

−4.41 ×10−17

−2.2 ×10−15 J atom−1

8.82 ×10−17 J atom−1

answer is B.

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Detailed Solution

IE=−E1E1 for He+=−19.6 ×10−18 J atom−1E1He+E1Li2+ = ZHe+2ZLi2+2−19.6 ×10−18E1Li2+=49Or E1Li2+=−19.6 ×9 × 10−184=−4.41 × 10−17 J atom−1

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