Ionisation energy of He+ is 19.6 × 10–18J atom–1. The energy of the first stationary state of Li2+ is
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a
– 4.41 × 10–18 J.atom–1
b
– 4.41 × 10–17 J.atom–1
c
– 44.1 × 10–16 J.atom–1
d
– 8.72 × 10–18 J.atom–1
answer is B.
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Detailed Solution
IP1 of He+ = 19.6 × 10-18 JIP of one electron species = E1 Z2IPHe+IPLi+2=2232IPLi+2=9419.6×10-18 = 4.41 × 10-17 J/atomMagnitude of IP1 = Magnitude of energy of electron in first orbitEnergy of e- in first orbit of Li+2 = - 4.41 × 10-17 J/atom