The Ionisation potential of Hydrogen is 2.17 × 10–11 erg/atom. The energy of the electron in the second orbit of the hydrogen atom is
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a
-2.17×10-112
b
-2.17×10-1122
c
-2.17×101722
d
-2.17×101122
answer is B.
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Detailed Solution
Ionization potential of H-atom has the same magnitude as energy of electron in first orbit of H-atom but opposite signSo IP1 of H-atom = +2.17 × 10-11 erg/atomE1 of H-atom = -2.17 × 10-11 erg/atomE2=-Z2n2E1=-1222E1(∵Z=1)=-2.17×101122 erg/atom