Q.
Ionization energy of Cl– is 349 KJ/mole. Approximate heat liberated when an electron is added to gaseous chlorine atom.
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a
5 × 10–20 J
b
5.9 × 10–19 J
c
6.5 × 10–20
d
3.49 × 10–26 J
answer is B.
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Detailed Solution
Given Cl-(g) →Cl(g)+e- ΔH = +349 KJCl(g) + e- → Cl- (g) ΔH = -349 KJ6.023x1023 atoms of Cl(g) →Cl-(g) releases 349 KjOne atom of Cl(g)→Cl- releases = = 59x10-23 KJ = 59x10-20 J = 5.9x10-19 J
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