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Q.

Ionization energy of He+ is 19.6×10−18J atom−1. The energy of the first stationary state of Li2+ is

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a

−4.41×10−18J atom−1

b

−4.41×10−17J atom−1

c

−4.41×10−16J atom−1

d

−8.72×10−18J atom−1

answer is B.

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Detailed Solution

E=−k×z2n2 I=k×z2n2 Iαz2n2 I1I2=z12n12×n22z22 19.6×10−18 JI2=49 I2=19.6×10−18×94J I2=−44.1×10−18 J
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