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The ionization energy of H is 13.6 electron volts (eV). The first and second ionization energies of He must be approximately.
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a
5 eV and 14 eV
b
5 eV and 54 eV
c
14 eV and 34 eV
d
24 eV and 54 eV
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Correct option is D
IP1 value of the He should be more than H. So I1 of He should be 24 eV. Then 2nd IP of He should be 54 eV.Similar Questions
The radius of the second Bohr orbit in terms of the Bohr radius,
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