The ionization energy of H is 13.6 electron volts (eV). The first and second ionization energies of He must be approximately.

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5 eV and 14 eV

5 eV and 54 eV

14 eV and 34 eV

24 eV and 54 eV

answer is D.

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Detailed Solution

IP1 value of the He should be more than H. So I1 of He should be 24 eV. Then 2nd IP of He should be 54 eV.

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