Ionization energy of He+ is 19.6×10-18J atom-1. The energy of the first stationary state (n = 1) of Li2+ is

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4.41×10-16 J atom-1

8.82×10-17 J atom-1

-2.2×10-15 J atom-1

-4.41×10-17 J atom-1

answer is D.

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Detailed Solution

Given I.E = 19.6×10-18I.E ∝ z2(I.E) Li2+/He+ = (9/4)×19.6×10-18= 4.41×10-17 ionisation energy is positive but orbital energy will be negative

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