Ionization energy for hydrogen atom in ergs, joules and ev respectively is:

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21.8×10−12,218×10−20,13.6

13.6×218×10−20,21.8×10−13

21.8×10−20,13.6,21.8×10−13

21.8×10−13,13.6,21.8×10−20

answer is A.

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Detailed Solution

∆E =-13.6 ×Z2n2ev (n=1 ,Z=1) =-13.6ev 1ev =1.6 ×10-19jouls so ∆E=13.6×1.6×10-19 =218×10-20 jouls 1joule =107ergs so∆E=218×10-20×107 ∆E =218×10-12ergs

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