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The ionization energy of solid NaCl is 180K.calmol−1. The dissolution of the solid in water in the form of ions is endothermic to the extent of 1K.cal.mol−1. If the solvation energies of Na+and Cl- and ions are in the ratio 6:5 what is the magnitude of enthalpy of hydration of sodium ion?

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answer is 97.63 K. .

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Detailed Solution

(ΔSolH)NaCl=(ΔiH)NaCl+(ΔHEH)Na++ΔHEHCl−If hydration of Na+& Cl- ions are 6x,5x respectively kcal/mol∴11x=−179x=−17911∴hydration enthalpy of Na+=6x=6−17911=−97.63K.calmol−1

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