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Ionization enthalpy of potassium = +422 kJ/mole;Electron gain enthalpy of chlorine = -349 kJ/mole;Sublimation enthalpy of potassium = +88 kJ/mole ;Bond dissociation enthalpy of chlorine = +243 kJ/mole ;Change in enthalpy for the process, Ks+12Cl2g→K+g+Cl-g will be

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a

+404 kJ

b

+323.5 kJ

c

+282.5 kJ

d

+161 kJ

answer is C.

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Detailed Solution

Ks→Kg, ∆H=+88 kJ...............1 Kg→K+g+e, ∆H=+422 kJ................2 12Cl2g→Clg, ∆H=+121.5 kJ/mole....3 Clg+e→Cl-g, ∆H=-349 kJ................4 Adding 1 ,2, 3and 4 Ks+12Cl2g→K+g+Cl-g, ∆H=+282.5 kJ ;

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