The ionization potential for the electron in the ground state of the hydrogen atom is 13.6 eV atom-1. What would be the ionization potential for the electron in the first excited state of Li2+ ?
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a
3.4 eV
b
10.2 eV
c
30.6 eV
d
6.8 eV
answer is C.
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Detailed Solution
ΔE=13.6Z21n12−1n22eV atom-1For the ionization of Li2+(z = 3) from first excited state, n1 =2 and n2 = ∞ Hence, IP=ΔE=13.6×32×122−1∞2= 30.6 eV