Iron exhibits bcc structure at room temperature. Above 900°C, it transforms to fcc structure. The ratio of density of iron at room temperature to that at 900°C (assuming molar mass and atomic radii of iron remains constant with temperature) is

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answer is 3.

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Detailed Solution

For bcc lattice :Z=2,a=4r3 For fcc lattice :Z=4,a=22r∴dR.T.d900°C=ZMNAa3bccZMNAa3fccGiven, molar mass and atom radii are constant.=2422r4r33=3342

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