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Irrespective of the strength of the ligand, the electronic  arrangement will be the same in the octahedral complex formed by 

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By Expert Faculty of Sri Chaitanya
a
Fe+3
b
Co+3
c
Mn+3
d
Cr+3

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detailed solution

Correct option is D

Cr+3  always has the same configuration irrespective of the strength of the ligand.It has two vacant orbitals to involve in  d2sp3 hybridization.Metal ions with d1, d2, d3 configurations have two or more than two vacant n-1d orbitals. They always involve in d2sp3hybridization


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Among NiCO4,NiCN42,NiCl42 species, the hybridization states at the Ni atom are, respectively

(At. no. of Ni = 28)

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