Irrespective of the strength of the ligand, the electronic  arrangement will be the same in the octahedral complex formed by

Cr+3  always has the same configuration irrespective of the strength of the ligand.It has two vacant orbitals to involve in  d2sp3 hybridization.Metal ions with d1, d2, d3 configurations have two or more than two vacant n-1d orbitals. They always involve in d2sp3hybridization