Q.

It takes 26 s for 10 mL of H2 to effuse through a porous membrane. It takes 130s for 10 mL of an unknown gas under identical condition to effuse. Hence, molecularweight of the unknown gas is (in g mol-l)

Moderate

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By Expert Faculty of Sri Chaitanya

100

answer is C.

(Detailed Solution Below)

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Detailed Solution

rH2=1026mLs−1rX=10130mLs−1rrX=1026/10130=m(X)mH2=m(X)2∴ m(X)=50gmol−1

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