First slide

Gaseous state

Question

It takes 26 s for 10 mL of H₂ to effuse through a porous membrane. It takes 130s for 10 mL of an unknown gas under identical condition to effuse. Hence, molecular
weight of the unknown gas is (in g mol^-l)

Moderate

A

100
B

80
C

50
D

40

Solution

$r_{H_{2}} = \frac{10}{26} {mLs}^{- 1}$
$r_{X} = \frac{10}{130} {mLs}^{- 1}$
$\frac{r}{r_{X}} = \frac{10}{26} / \frac{10}{130} = \sqrt{\frac{m (X)}{m (H_{2})}} = \sqrt{\frac{m (X)}{2}}$
$∴ m (X) = 50 g {mol}^{- 1}$

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