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a
2–methyl –3– oxo–hex–4–ynoic acid
b
2–ethyl –3–oxo–hex–4–ynoic acid
c
5–ethyl–4–oxo–hex–2–ynoic acid
d
5–methyl–4–oxo–hex–2–ynoic acid
answer is B.
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Detailed Solution
Root word is….hex;Principal functional group is -COOH….oic acid ….numbering must start from -COOH group;on 2nd carbon….ethyl; on 3rd carbon …oxo or keto ; between 4th and 5th carbons …. a triple bond;